6549740253 has 24 divisors (see below), whose sum is σ = 10863534656. Its totient is φ = 3724963200.

The previous prime is 6549740221. The next prime is 6549740261. The reversal of 6549740253 is 3520479456.

It is not a de Polignac number, because 6549740253 - 2⁵ = 6549740221 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 6549740199 and 6549740208.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (6549742253) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 233068 + ... + 259653.

Almost surely, 2^6549740253 is an apocalyptic number.

6549740253 is a gapful number since it is divisible by the number (63) formed by its first and last digit.

It is an amenable number.

6549740253 is a deficient number, since it is larger than the sum of its proper divisors (4313794403).

6549740253 is a wasteful number, since it uses less digits than its factorization.

6549740253 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 492945 (or 492942 counting only the distinct ones).

The product of its (nonzero) digits is 907200, while the sum is 45.

The square root of 6549740253 is about 80930.4655429585. The cubic root of 6549740253 is about 1871.0038985160.

The spelling of 6549740253 in words is "six billion, five hundred forty-nine million, seven hundred forty thousand, two hundred fifty-three".