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6703128623159 is a prime number
BaseRepresentation
bin110000110001011000110…
…0110011011100000110111
3212201210221120002110202222
41201202301212123200313
51334311001411420114
622131212541352555
71261166530125053
oct141426146334067
925653846073688
106703128623159
1121548653a2a21
1290314026875b
13398143a37137
1419260c81cc63
15b956ca3e98e
hex618b199b837

6703128623159 has 2 divisors, whose sum is σ = 6703128623160. Its totient is φ = 6703128623158.

The previous prime is 6703128623117. The next prime is 6703128623161. The reversal of 6703128623159 is 9513268213076.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 6703128623159 - 228 = 6702860187703 is a prime.

It is a super-2 number, since 2×67031286231592 (a number of 26 digits) contains 22 as substring.

Together with 6703128623161, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 6703128623159.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (6703128623959) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3351564311579 + 3351564311580.

It is an arithmetic number, because the mean of its divisors is an integer number (3351564311580).

Almost surely, 26703128623159 is an apocalyptic number.

6703128623159 is a deficient number, since it is larger than the sum of its proper divisors (1).

6703128623159 is an equidigital number, since it uses as much as digits as its factorization.

6703128623159 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3265920, while the sum is 53.

The spelling of 6703128623159 in words is "six trillion, seven hundred three billion, one hundred twenty-eight million, six hundred twenty-three thousand, one hundred fifty-nine".