Base | Representation |
---|---|
bin | 111111010101111000… |
… | …001110000010000110 |
3 | 20111112221001220201000 |
4 | 333111320032002012 |
5 | 2103242233401430 |
6 | 51124502114130 |
7 | 4625264132061 |
oct | 772570160206 |
9 | 214487056630 |
10 | 68012793990 |
11 | 269314a3859 |
12 | 1122141b946 |
13 | 654b82c7cb |
14 | 3412b2b8d8 |
15 | 1b80e28e60 |
hex | fd5e0e086 |
68012793990 has 32 divisors (see below), whose sum is σ = 181367451360. Its totient is φ = 18136744992.
The previous prime is 68012793941. The next prime is 68012794001. The reversal of 68012793990 is 9939721086.
68012793990 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (54).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 125949349 + ... + 125949888.
It is an arithmetic number, because the mean of its divisors is an integer number (5667732855).
Almost surely, 268012793990 is an apocalyptic number.
68012793990 is an abundant number, since it is smaller than the sum of its proper divisors (113354657370).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
68012793990 is a wasteful number, since it uses less digits than its factorization.
68012793990 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 251899253 (or 251899247 counting only the distinct ones).
The product of its (nonzero) digits is 1469664, while the sum is 54.
The spelling of 68012793990 in words is "sixty-eight billion, twelve million, seven hundred ninety-three thousand, nine hundred ninety".
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