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69664811712703 is a prime number
BaseRepresentation
bin11111101011100000110100…
…10110110000000010111111
3100010122220001111201112111121
433311300122112300002333
533112342013244301303
6404055323411131411
720450054656141444
oct1765603226600277
9303586044645447
1069664811712703
1120219754065859
1279916105a3b67
132cb449596b42c
14132bb1b2039cb
1580c21ceb29bd
hex3f5c1a5b00bf

69664811712703 has 2 divisors, whose sum is σ = 69664811712704. Its totient is φ = 69664811712702.

The previous prime is 69664811712701. The next prime is 69664811712739. The reversal of 69664811712703 is 30721711846696.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 69664811712703 - 21 = 69664811712701 is a prime.

It is a super-2 number, since 2×696648117127032 (a number of 28 digits) contains 22 as substring.

Together with 69664811712701, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (69664811712701) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 34832405856351 + 34832405856352.

It is an arithmetic number, because the mean of its divisors is an integer number (34832405856352).

Almost surely, 269664811712703 is an apocalyptic number.

69664811712703 is a deficient number, since it is larger than the sum of its proper divisors (1).

69664811712703 is an equidigital number, since it uses as much as digits as its factorization.

69664811712703 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18289152, while the sum is 61.

The spelling of 69664811712703 in words is "sixty-nine trillion, six hundred sixty-four billion, eight hundred eleven million, seven hundred twelve thousand, seven hundred three".