Base | Representation |
---|---|
bin | 100001001001111110… |
… | …1101010110001111100 |
3 | 20210210011220221210200 |
4 | 1002103331222301330 |
5 | 2131310141043000 |
6 | 52413143403500 |
7 | 5100310052223 |
oct | 1022375526174 |
9 | 223704827720 |
10 | 71201893500 |
11 | 28218681491 |
12 | 11971453590 |
13 | 693945293a |
14 | 36364b9cba |
15 | 1cbadc2500 |
hex | 1093f6ac7c |
71201893500 has 288 divisors, whose sum is σ = 240731906688. Its totient is φ = 17669836800.
The previous prime is 71201893459. The next prime is 71201893507. The reversal of 71201893500 is 539810217.
71201893500 is a `hidden beast` number, since 7 + 120 + 189 + 350 + 0 = 666.
It is a Harshad number since it is a multiple of its sum of digits (36).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (71201893507) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 3820204 + ... + 3838796.
It is an arithmetic number, because the mean of its divisors is an integer number (835874676).
Almost surely, 271201893500 is an apocalyptic number.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 71201893500, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (120365953344).
71201893500 is an abundant number, since it is smaller than the sum of its proper divisors (169530013188).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
71201893500 is a wasteful number, since it uses less digits than its factorization.
71201893500 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18678 (or 18663 counting only the distinct ones).
The product of its (nonzero) digits is 15120, while the sum is 36.
The spelling of 71201893500 in words is "seventy-one billion, two hundred one million, eight hundred ninety-three thousand, five hundred".
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