Base | Representation |
---|---|
bin | 101100010011100… |
… | …000001011100101 |
3 | 1220210200001200222 |
4 | 230103200023211 |
5 | 3010241410203 |
6 | 201431414125 |
7 | 24264013463 |
oct | 5423401345 |
9 | 1823601628 |
10 | 743310053 |
11 | 351640932 |
12 | 188b24345 |
13 | bacc4745 |
14 | 70a0d833 |
15 | 453ca038 |
hex | 2c4e02e5 |
743310053 has 2 divisors, whose sum is σ = 743310054. Its totient is φ = 743310052.
The previous prime is 743310047. The next prime is 743310059. The reversal of 743310053 is 350013347.
It is a balanced prime because it is at equal distance from previous prime (743310047) and next prime (743310059).
It can be written as a sum of positive squares in only one way, i.e., 712195969 + 31114084 = 26687^2 + 5578^2 .
It is an emirp because it is prime and its reverse (350013347) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 743310053 - 24 = 743310037 is a prime.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (743310059) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 371655026 + 371655027.
It is an arithmetic number, because the mean of its divisors is an integer number (371655027).
Almost surely, 2743310053 is an apocalyptic number.
It is an amenable number.
743310053 is a deficient number, since it is larger than the sum of its proper divisors (1).
743310053 is an equidigital number, since it uses as much as digits as its factorization.
743310053 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3780, while the sum is 26.
The square root of 743310053 is about 27263.7131183557. The cubic root of 743310053 is about 905.8507929693.
The spelling of 743310053 in words is "seven hundred forty-three million, three hundred ten thousand, fifty-three".
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