75113301 has 4 divisors (see below), whose sum is σ = 100151072. Its totient is φ = 50075532.

The previous prime is 75113299. The next prime is 75113309. The reversal of 75113301 is 10331157.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10331157 = 3 ⋅3443719.

It is not a de Polignac number, because 75113301 - 2¹ = 75113299 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (75113309) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12518881 + ... + 12518886.

It is an arithmetic number, because the mean of its divisors is an integer number (25037768).

Almost surely, 2^75113301 is an apocalyptic number.

It is an amenable number.

75113301 is a deficient number, since it is larger than the sum of its proper divisors (25037771).

75113301 is a wasteful number, since it uses less digits than its factorization.

75113301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 25037770.

The product of its (nonzero) digits is 315, while the sum is 21.

The square root of 75113301 is about 8666.7930054894. The cubic root of 75113301 is about 421.9285852813.

Adding to 75113301 its reverse (10331157), we get a palindrome (85444458).

The spelling of 75113301 in words is "seventy-five million, one hundred thirteen thousand, three hundred one".