Base | Representation |
---|---|
bin | 100011011100100101… |
… | …0100100101101111111 |
3 | 21021111000002111111002 |
4 | 1012321022210231333 |
5 | 2221343434011311 |
6 | 54545225120515 |
7 | 5333230555061 |
oct | 1067112445577 |
9 | 237430074432 |
10 | 76121000831 |
11 | 2a312358647 |
12 | 1290492913b |
13 | 72415caa35 |
14 | 3981921731 |
15 | 1ea7b9a93b |
hex | 11b92a4b7f |
76121000831 has 2 divisors, whose sum is σ = 76121000832. Its totient is φ = 76121000830.
The previous prime is 76121000777. The next prime is 76121000833. The reversal of 76121000831 is 13800012167.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 76121000831 - 214 = 76120984447 is a prime.
It is a super-2 number, since 2×761210008312 (a number of 23 digits) contains 22 as substring.
Together with 76121000833, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 76121000794 and 76121000803.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (76121000833) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 38060500415 + 38060500416.
It is an arithmetic number, because the mean of its divisors is an integer number (38060500416).
Almost surely, 276121000831 is an apocalyptic number.
76121000831 is a deficient number, since it is larger than the sum of its proper divisors (1).
76121000831 is an equidigital number, since it uses as much as digits as its factorization.
76121000831 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2016, while the sum is 29.
Adding to 76121000831 its reverse (13800012167), we get a palindrome (89921012998).
The spelling of 76121000831 in words is "seventy-six billion, one hundred twenty-one million, eight hundred thirty-one", and thus it is an aban number.
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •