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80253943 = 7111042259
BaseRepresentation
bin1001100100010…
…01001111110111
312121000022201021
410302021033313
5131021111233
611544042011
71663101340
oct462111767
9177008637
1080253943
1141334a80
1222a63307
131381bb53
14a9310c7
1570a3e2d
hex4c893f7

80253943 has 8 divisors (see below), whose sum is σ = 100056960. Its totient is φ = 62535480.

The previous prime is 80253941. The next prime is 80254019. The reversal of 80253943 is 34935208.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 80253943 - 21 = 80253941 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 80253899 and 80253908.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (80253941) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 521053 + ... + 521206.

It is an arithmetic number, because the mean of its divisors is an integer number (12507120).

Almost surely, 280253943 is an apocalyptic number.

80253943 is a deficient number, since it is larger than the sum of its proper divisors (19803017).

80253943 is a wasteful number, since it uses less digits than its factorization.

80253943 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1042277.

The product of its (nonzero) digits is 25920, while the sum is 34.

The square root of 80253943 is about 8958.4565076803. The cubic root of 80253943 is about 431.3423761223.

It can be divided in two parts, 802 and 53943, that added together give a palindrome (54745).

The spelling of 80253943 in words is "eighty million, two hundred fifty-three thousand, nine hundred forty-three".

Divisors: 1 7 11 77 1042259 7295813 11464849 80253943