811171434613 has 2 divisors, whose sum is σ = 811171434614. Its totient is φ = 811171434612.

The previous prime is 811171434611. The next prime is 811171434629. The reversal of 811171434613 is 316434171118.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 722401403364 + 88770031249 = 849942^2 + 297943^2 .

It is a cyclic number.

It is not a de Polignac number, because 811171434613 - 2¹ = 811171434611 is a prime.

It is a super-2 number, since 2×811171434613² (a number of 25 digits) contains 22 as substring.

Together with 811171434611, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (811171434611) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 405585717306 + 405585717307.

It is an arithmetic number, because the mean of its divisors is an integer number (405585717307).

Almost surely, 2^811171434613 is an apocalyptic number.

It is an amenable number.

811171434613 is a deficient number, since it is larger than the sum of its proper divisors (1).

811171434613 is an equidigital number, since it uses as much as digits as its factorization.

811171434613 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 48384, while the sum is 40.

The spelling of 811171434613 in words is "eight hundred eleven billion, one hundred seventy-one million, four hundred thirty-four thousand, six hundred thirteen".