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83111000011133 is a prime number
BaseRepresentation
bin10010111001011011001001…
…101000011111000101111101
3101220021100000111020002211112
4102321123021220133011331
541343142312000324013
6452432355531331405
723335400025653303
oct2271331150370575
9356240014202745
1083111000011133
11245331a4897106
1293a35758b0b65
13374b445101283
1416748457c2273
15991d93e59ba8
hex4b96c9a1f17d

83111000011133 has 2 divisors, whose sum is σ = 83111000011134. Its totient is φ = 83111000011132.

The previous prime is 83111000011097. The next prime is 83111000011181. The reversal of 83111000011133 is 33111000011138.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 60671044662244 + 22439955348889 = 7789162^2 + 4737083^2 .

It is a cyclic number.

It is not a de Polignac number, because 83111000011133 - 214 = 83110999994749 is a prime.

It is a super-2 number, since 2×831110000111332 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 83111000011099 and 83111000011108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (83111000011733) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 41555500005566 + 41555500005567.

It is an arithmetic number, because the mean of its divisors is an integer number (41555500005567).

Almost surely, 283111000011133 is an apocalyptic number.

It is an amenable number.

83111000011133 is a deficient number, since it is larger than the sum of its proper divisors (1).

83111000011133 is an equidigital number, since it uses as much as digits as its factorization.

83111000011133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 23.

The spelling of 83111000011133 in words is "eighty-three trillion, one hundred eleven billion, eleven thousand, one hundred thirty-three".