83540111 has 2 divisors, whose sum is σ = 83540112. Its totient is φ = 83540110.

The previous prime is 83540101. The next prime is 83540113. The reversal of 83540111 is 11104538.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-83540111 is a prime.

Together with 83540113, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (83540113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 41770055 + 41770056.

It is an arithmetic number, because the mean of its divisors is an integer number (41770056).

Almost surely, 2^83540111 is an apocalyptic number.

83540111 is a deficient number, since it is larger than the sum of its proper divisors (1).

83540111 is an equidigital number, since it uses as much as digits as its factorization.

83540111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 480, while the sum is 23.

The square root of 83540111 is about 9140.0279540054. The cubic root of 83540111 is about 437.1512078262.

Adding to 83540111 its reverse (11104538), we get a palindrome (94644649).

The spelling of 83540111 in words is "eighty-three million, five hundred forty thousand, one hundred eleven".