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86000011000093 is a prime number
BaseRepresentation
bin10011100011011101110000…
…000110110011100100011101
3102021111112001122002102211001
4103203131300012303210131
542233011010304000333
6502523505403230301
724054203305125001
oct2343356006634435
9367445048072731
1086000011000093
1125447444215083
12978b465818391
1338ca9c6573b38
1417345cc008701
159e20ce845b7d
hex4e37701b391d

86000011000093 has 2 divisors, whose sum is σ = 86000011000094. Its totient is φ = 86000011000092.

The previous prime is 86000011000067. The next prime is 86000011000121. The reversal of 86000011000093 is 39000011000068.

It is a happy number.

It is an a-pointer prime, because the next prime (86000011000121) can be obtained adding 86000011000093 to its sum of digits (28).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 66315908197764 + 19684102802329 = 8143458^2 + 4436677^2 .

It is a cyclic number.

It is not a de Polignac number, because 86000011000093 - 213 = 86000010991901 is a prime.

It is a super-2 number, since 2×860000110000932 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (86000011009093) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 43000005500046 + 43000005500047.

It is an arithmetic number, because the mean of its divisors is an integer number (43000005500047).

Almost surely, 286000011000093 is an apocalyptic number.

It is an amenable number.

86000011000093 is a deficient number, since it is larger than the sum of its proper divisors (1).

86000011000093 is an equidigital number, since it uses as much as digits as its factorization.

86000011000093 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 28.

The spelling of 86000011000093 in words is "eighty-six trillion, eleven million, ninety-three", and thus it is an aban number and an uban number.