Base | Representation |
---|---|
bin | 101001110001010010… |
… | …0010000000000001111 |
3 | 22120112101022111122011 |
4 | 1103202210100000033 |
5 | 2432201311440341 |
6 | 105112521002051 |
7 | 6323601444112 |
oct | 1234244200017 |
9 | 276471274564 |
10 | 89700499471 |
11 | 350506589a0 |
12 | 15474623327 |
13 | 85c6a6a92b |
14 | 44ad218579 |
15 | 24eee1ab81 |
hex | 14e291000f |
89700499471 has 4 divisors (see below), whose sum is σ = 97855090344. Its totient is φ = 81545908600.
The previous prime is 89700499429. The next prime is 89700499487. The reversal of 89700499471 is 17499400798.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 89700499471 - 215 = 89700466703 is a prime.
It is a super-3 number, since 3×897004994713 (a number of 34 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (89700499871) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4077295420 + ... + 4077295441.
It is an arithmetic number, because the mean of its divisors is an integer number (24463772586).
Almost surely, 289700499471 is an apocalyptic number.
89700499471 is a deficient number, since it is larger than the sum of its proper divisors (8154590873).
89700499471 is a wasteful number, since it uses less digits than its factorization.
89700499471 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8154590872.
The product of its (nonzero) digits is 4572288, while the sum is 58.
The spelling of 89700499471 in words is "eighty-nine billion, seven hundred million, four hundred ninety-nine thousand, four hundred seventy-one".
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