Base | Representation |
---|---|
bin | 1000010001101100010110… |
… | …0101000010110101111111 |
3 | 1012012221211111222200100111 |
4 | 2010123011211002311333 |
5 | 2143043403210233310 |
6 | 31204301404210451 |
7 | 1626312600650104 |
oct | 204330545026577 |
9 | 35187744880314 |
10 | 9100055555455 |
11 | 2999348139927 |
12 | 102b79a239a27 |
13 | 510193051387 |
14 | 236633288aab |
15 | 10baa773c28a |
hex | 846c5942d7f |
9100055555455 has 16 divisors (see below), whose sum is σ = 11676902981184. Its totient is φ = 6783966860800.
The previous prime is 9100055555453. The next prime is 9100055555471. The reversal of 9100055555455 is 5545555500019.
9100055555455 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 9100055555455 - 21 = 9100055555453 is a prime.
It is a super-2 number, since 2×91000555554552 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 9100055555399 and 9100055555408.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (9100055555453) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 529988827 + ... + 530005996.
It is an arithmetic number, because the mean of its divisors is an integer number (729806436324).
Almost surely, 29100055555455 is an apocalyptic number.
9100055555455 is a deficient number, since it is larger than the sum of its proper divisors (2576847425729).
9100055555455 is a wasteful number, since it uses less digits than its factorization.
9100055555455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1059994946.
The product of its (nonzero) digits is 2812500, while the sum is 49.
The spelling of 9100055555455 in words is "nine trillion, one hundred billion, fifty-five million, five hundred fifty-five thousand, four hundred fifty-five".
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