Base | Representation |
---|---|
bin | 10100111010111101001111… |
… | …001000011000110000000111 |
3 | 110001210022010012021002012021 |
4 | 110322331033020120300013 |
5 | 44030012404431341212 |
6 | 523405530222304011 |
7 | 25244451226210663 |
oct | 2472751710306007 |
9 | 401708105232167 |
10 | 92012411980807 |
11 | 2735527689391a |
12 | a3a0756728007 |
13 | 3c4596bb61236 |
14 | 18a15d2b938a3 |
15 | a986c2358307 |
hex | 53af4f218c07 |
92012411980807 has 2 divisors, whose sum is σ = 92012411980808. Its totient is φ = 92012411980806.
The previous prime is 92012411980739. The next prime is 92012411980859. The reversal of 92012411980807 is 70808911421029.
It is an a-pointer prime, because the next prime (92012411980859) can be obtained adding 92012411980807 to its sum of digits (52).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 92012411980807 - 27 = 92012411980679 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (92012411980897) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 46006205990403 + 46006205990404.
It is an arithmetic number, because the mean of its divisors is an integer number (46006205990404).
Almost surely, 292012411980807 is an apocalyptic number.
92012411980807 is a deficient number, since it is larger than the sum of its proper divisors (1).
92012411980807 is an equidigital number, since it uses as much as digits as its factorization.
92012411980807 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 580608, while the sum is 52.
The spelling of 92012411980807 in words is "ninety-two trillion, twelve billion, four hundred eleven million, nine hundred eighty thousand, eight hundred seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.105 sec. • engine limits •