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94416996941 is a prime number
BaseRepresentation
bin101011111101110110…
…0010000101001001101
3100000201002020101211122
41113323230100221031
53021331222400231
6111212523530325
76551512142441
oct1277354205115
9300632211748
1094416996941
1137050a2a293
12163700899a5
138b98c56837
1447d979c821
1526c902177b
hex15fbb10a4d

94416996941 has 2 divisors, whose sum is σ = 94416996942. Its totient is φ = 94416996940.

The previous prime is 94416996917. The next prime is 94416996943. The reversal of 94416996941 is 14969961449.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 91839302500 + 2577694441 = 303050^2 + 50771^2 .

It is an emirp because it is prime and its reverse (14969961449) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 94416996941 - 214 = 94416980557 is a prime.

It is a super-3 number, since 3×944169969413 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 94416996943, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (94416996943) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 47208498470 + 47208498471.

It is an arithmetic number, because the mean of its divisors is an integer number (47208498471).

Almost surely, 294416996941 is an apocalyptic number.

It is an amenable number.

94416996941 is a deficient number, since it is larger than the sum of its proper divisors (1).

94416996941 is an equidigital number, since it uses as much as digits as its factorization.

94416996941 is an evil number, because the sum of its binary digits is even.

The product of its digits is 15116544, while the sum is 62.

The spelling of 94416996941 in words is "ninety-four billion, four hundred sixteen million, nine hundred ninety-six thousand, nine hundred forty-one".