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95125127 is a prime number
BaseRepresentation
bin1011010101101…
…11111010000111
320121222212010212
411222313322013
5143323001002
613234510035
72233356506
oct552677207
9217885125
1095125127
1149771a09
1227a3531b
1316927976
14c8c283d
158540352
hex5ab7e87

95125127 has 2 divisors, whose sum is σ = 95125128. Its totient is φ = 95125126.

The previous prime is 95125123. The next prime is 95125139. The reversal of 95125127 is 72152159.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 95125127 - 22 = 95125123 is a prime.

It is a super-2 number, since 2×951251272 = 18097579573532258, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 95125093 and 95125102.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (95125123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 47562563 + 47562564.

It is an arithmetic number, because the mean of its divisors is an integer number (47562564).

Almost surely, 295125127 is an apocalyptic number.

95125127 is a deficient number, since it is larger than the sum of its proper divisors (1).

95125127 is an equidigital number, since it uses as much as digits as its factorization.

95125127 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6300, while the sum is 32.

The square root of 95125127 is about 9753.2111122440. The cubic root of 95125127 is about 456.4905062873.

The spelling of 95125127 in words is "ninety-five million, one hundred twenty-five thousand, one hundred twenty-seven".