Base | Representation |
---|---|
bin | 10001110000000100… |
… | …00101001010110101 |
3 | 220121011101101000122 |
4 | 20320002011022311 |
5 | 124004140113044 |
6 | 4213353021325 |
7 | 455106461441 |
oct | 107002051265 |
9 | 26534341018 |
10 | 9530004149 |
11 | 4050491196 |
12 | 1a1b6b4845 |
13 | b8b50c213 |
14 | 66597b821 |
15 | 3ab9bedee |
hex | 2380852b5 |
9530004149 has 2 divisors, whose sum is σ = 9530004150. Its totient is φ = 9530004148.
The previous prime is 9530004137. The next prime is 9530004151. The reversal of 9530004149 is 9414000359.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5748369124 + 3781635025 = 75818^2 + 61495^2 .
It is a cyclic number.
It is not a de Polignac number, because 9530004149 - 232 = 5235036853 is a prime.
Together with 9530004151, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (9530004199) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4765002074 + 4765002075.
It is an arithmetic number, because the mean of its divisors is an integer number (4765002075).
Almost surely, 29530004149 is an apocalyptic number.
It is an amenable number.
9530004149 is a deficient number, since it is larger than the sum of its proper divisors (1).
9530004149 is an equidigital number, since it uses as much as digits as its factorization.
9530004149 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 19440, while the sum is 35.
The square root of 9530004149 is about 97621.7401453180. The cubic root of 9530004149 is about 2120.1391380289.
The spelling of 9530004149 in words is "nine billion, five hundred thirty million, four thousand, one hundred forty-nine".
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