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97254243341 is a prime number
BaseRepresentation
bin101101010010011001…
…1011111110000001101
3100022000211000110012122
41122210303133300031
53043134041241331
6112402235542325
710012023300023
oct1324463376015
9308024013178
1097254243341
1138277537522
1216a222ba9a5
13922b9c5168
1449c851a713
1527e316717b
hex16a4cdfc0d

97254243341 has 2 divisors, whose sum is σ = 97254243342. Its totient is φ = 97254243340.

The previous prime is 97254243337. The next prime is 97254243343. The reversal of 97254243341 is 14334245279.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 67055102500 + 30199140841 = 258950^2 + 173779^2 .

It is a cyclic number.

It is not a de Polignac number, because 97254243341 - 22 = 97254243337 is a prime.

Together with 97254243343, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 97254243292 and 97254243301.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (97254243343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 48627121670 + 48627121671.

It is an arithmetic number, because the mean of its divisors is an integer number (48627121671).

Almost surely, 297254243341 is an apocalyptic number.

It is an amenable number.

97254243341 is a deficient number, since it is larger than the sum of its proper divisors (1).

97254243341 is an equidigital number, since it uses as much as digits as its factorization.

97254243341 is an evil number, because the sum of its binary digits is even.

The product of its digits is 725760, while the sum is 44.

The spelling of 97254243341 in words is "ninety-seven billion, two hundred fifty-four million, two hundred forty-three thousand, three hundred forty-one".