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989925000502213 is a prime number
BaseRepresentation
bin1110000100010101001110000…
…0000000100101101111000101
311210211000220110100010210111101
43201011103200000211233011
52014222412400112032323
613425221133410540101
7415340502225402226
oct34105234000455705
94724026410123441
10989925000502213
112674699205458a6
129303a11b897631
13336496b0a706b9
14136648a8ba124d
15796a34addedad
hex38454e0025bc5

989925000502213 has 2 divisors, whose sum is σ = 989925000502214. Its totient is φ = 989925000502212.

The previous prime is 989925000502189. The next prime is 989925000502237. The reversal of 989925000502213 is 312205000529989.

It is a happy number.

It is a balanced prime because it is at equal distance from previous prime (989925000502189) and next prime (989925000502237).

It can be written as a sum of positive squares in only one way, i.e., 720127851699204 + 269797148803009 = 26835198^2 + 16425503^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-989925000502213 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (989925000502813) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 494962500251106 + 494962500251107.

It is an arithmetic number, because the mean of its divisors is an integer number (494962500251107).

Almost surely, 2989925000502213 is an apocalyptic number.

It is an amenable number.

989925000502213 is a deficient number, since it is larger than the sum of its proper divisors (1).

989925000502213 is an equidigital number, since it uses as much as digits as its factorization.

989925000502213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3499200, while the sum is 55.

The spelling of 989925000502213 in words is "nine hundred eighty-nine trillion, nine hundred twenty-five billion, five hundred two thousand, two hundred thirteen".