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991632375341 is a prime number
BaseRepresentation
bin11100110111000011110…
…01010011111000101101
310111210120120021001100122
432123201321103320231
5112221330342002331
62035314415134325
7131433401054606
oct16334171237055
93453516231318
10991632375341
11352604695713
121402278143a5
137268383b34a
1435dd1004dad
151abdbd5017b
hexe6e1e53e2d

991632375341 has 2 divisors, whose sum is σ = 991632375342. Its totient is φ = 991632375340.

The previous prime is 991632375317. The next prime is 991632375343. The reversal of 991632375341 is 143573236199.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 945213672841 + 46418702500 = 972221^2 + 215450^2 .

It is an emirp because it is prime and its reverse (143573236199) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-991632375341 is a prime.

Together with 991632375343, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (991632375343) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 495816187670 + 495816187671.

It is an arithmetic number, because the mean of its divisors is an integer number (495816187671).

Almost surely, 2991632375341 is an apocalyptic number.

It is an amenable number.

991632375341 is a deficient number, since it is larger than the sum of its proper divisors (1).

991632375341 is an equidigital number, since it uses as much as digits as its factorization.

991632375341 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3674160, while the sum is 53.

The spelling of 991632375341 in words is "nine hundred ninety-one billion, six hundred thirty-two million, three hundred seventy-five thousand, three hundred forty-one".