999113149 has 2 divisors, whose sum is σ = 999113150. Its totient is φ = 999113148.

The previous prime is 999113147. The next prime is 999113161. The reversal of 999113149 is 941311999.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 848265625 + 150847524 = 29125^2 + 12282^2 .

It is an emirp because it is prime and its reverse (941311999) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 999113149 - 2¹ = 999113147 is a prime.

Together with 999113147, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 999113099 and 999113108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (999113147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 499556574 + 499556575.

It is an arithmetic number, because the mean of its divisors is an integer number (499556575).

Almost surely, 2^999113149 is an apocalyptic number.

It is an amenable number.

999113149 is a deficient number, since it is larger than the sum of its proper divisors (1).

999113149 is an equidigital number, since it uses as much as digits as its factorization.

999113149 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 78732, while the sum is 46.

The square root of 999113149 is about 31608.7511458457. The cubic root of 999113149 is about 999.7042955675.

The spelling of 999113149 in words is "nine hundred ninety-nine million, one hundred thirteen thousand, one hundred forty-nine".