Base | Representation |
---|---|
bin | 101110100100001111… |
… | …0001110011110100111 |
3 | 100120010011212222220221 |
4 | 1131020132032132213 |
5 | 3114300013142413 |
6 | 113534525505211 |
7 | 10140045042244 |
oct | 1351036163647 |
9 | 316104788827 |
10 | 100000130983 |
11 | 39456515555 |
12 | 17469a12207 |
13 | 957885724c |
14 | 4ba90965cb |
15 | 290426368d |
hex | 174878e7a7 |
100000130983 has 2 divisors, whose sum is σ = 100000130984. Its totient is φ = 100000130982.
The previous prime is 100000130959. The next prime is 100000131001. The reversal of 100000130983 is 389031000001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 100000130983 - 233 = 91410196391 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100000130683) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50000065491 + 50000065492.
It is an arithmetic number, because the mean of its divisors is an integer number (50000065492).
Almost surely, 2100000130983 is an apocalyptic number.
100000130983 is a deficient number, since it is larger than the sum of its proper divisors (1).
100000130983 is an equidigital number, since it uses as much as digits as its factorization.
100000130983 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 25.
Adding to 100000130983 its reverse (389031000001), we get a palindrome (489031130984).
The spelling of 100000130983 in words is "one hundred billion, one hundred thirty thousand, nine hundred eighty-three".
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