10000122002111 has 2 divisors, whose sum is σ = 10000122002112. Its totient is φ = 10000122002110.

The previous prime is 10000122002093. The next prime is 10000122002113. The reversal of 10000122002111 is 11120022100001.

It is a strong prime.

It is an emirp because it is prime and its reverse (11120022100001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10000122002111 - 2¹⁴ = 10000121985727 is a prime.

Together with 10000122002113, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 10000122002092 and 10000122002101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10000122002113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5000061001055 + 5000061001056.

It is an arithmetic number, because the mean of its divisors is an integer number (5000061001056).

Almost surely, 2^{10000122002111} is an apocalyptic number.

10000122002111 is a deficient number, since it is larger than the sum of its proper divisors (1).

10000122002111 is an equidigital number, since it uses as much as digits as its factorization.

10000122002111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8, while the sum is 11.

Adding to 10000122002111 its reverse (11120022100001), we get a palindrome (21120144102112).

The spelling of 10000122002111 in words is "ten trillion, one hundred twenty-two million, two thousand, one hundred eleven".