Base | Representation |
---|---|
bin | 1001000110001000101011… |
… | …0001101000111000001111 |
3 | 1022102002100201201221211021 |
4 | 2101202022301220320033 |
5 | 2302324033101232031 |
6 | 33134222422335011 |
7 | 2051356255341436 |
oct | 221421261507017 |
9 | 38362321657737 |
10 | 10001012133391 |
11 | 32064506948a4 |
12 | 115631a88a467 |
13 | 577125a53316 |
14 | 2680a171811d |
15 | 125238c1e511 |
hex | 9188ac68e0f |
10001012133391 has 2 divisors, whose sum is σ = 10001012133392. Its totient is φ = 10001012133390.
The previous prime is 10001012133311. The next prime is 10001012133451. The reversal of 10001012133391 is 19333121010001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10001012133391 - 243 = 1204919111183 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10001012133311) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5000506066695 + 5000506066696.
It is an arithmetic number, because the mean of its divisors is an integer number (5000506066696).
Almost surely, 210001012133391 is an apocalyptic number.
10001012133391 is a deficient number, since it is larger than the sum of its proper divisors (1).
10001012133391 is an equidigital number, since it uses as much as digits as its factorization.
10001012133391 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 486, while the sum is 25.
Adding to 10001012133391 its reverse (19333121010001), we get a palindrome (29334133143392).
The spelling of 10001012133391 in words is "ten trillion, one billion, twelve million, one hundred thirty-three thousand, three hundred ninety-one".
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