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1000102112117 is a prime number
BaseRepresentation
bin11101000110110101011…
…10110010101101110101
310112121102211120020222022
432203122232302231311
5112341202120041432
62043235055042525
7132153314456003
oct16433256625565
93477384506868
101000102112117
1135616062a279
121419b0210445
137340349b804
1436595c27a73
151b0356d6b12
hexe8dabb2b75

1000102112117 has 2 divisors, whose sum is σ = 1000102112118. Its totient is φ = 1000102112116.

The previous prime is 1000102112089. The next prime is 1000102112123. The reversal of 1000102112117 is 7112112010001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 725834137681 + 274267974436 = 851959^2 + 523706^2 .

It is an emirp because it is prime and its reverse (7112112010001) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1000102112117 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1000102112095 and 1000102112104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1000102112617) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500051056058 + 500051056059.

It is an arithmetic number, because the mean of its divisors is an integer number (500051056059).

Almost surely, 21000102112117 is an apocalyptic number.

It is an amenable number.

1000102112117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1000102112117 is an equidigital number, since it uses as much as digits as its factorization.

1000102112117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 28, while the sum is 17.

Adding to 1000102112117 its reverse (7112112010001), we get a palindrome (8112214122118).

The spelling of 1000102112117 in words is "one trillion, one hundred two million, one hundred twelve thousand, one hundred seventeen".