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10001031121310 = 251000103112131
BaseRepresentation
bin1001000110001000101111…
…1010000100100110011110
31022102002102001110122100112
42101202023322010212132
52302324102431340220
633134224341330022
72051356605624005
oct221421372044636
938362361418315
1010001031121310
113206460383799
121156325106912
13577129970b88
142680a405bc3c
1512523a7205c5
hex9188be8499e

10001031121310 has 8 divisors (see below), whose sum is σ = 18001856018376. Its totient is φ = 4000412448520.

The previous prime is 10001031121303. The next prime is 10001031121327. The reversal of 10001031121310 is 1312113010001.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×100010311213102 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 500051556056 + ... + 500051556075.

It is an arithmetic number, because the mean of its divisors is an integer number (2250232002297).

Almost surely, 210001031121310 is an apocalyptic number.

10001031121310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

10001031121310 is a deficient number, since it is larger than the sum of its proper divisors (8000824897066).

10001031121310 is a wasteful number, since it uses less digits than its factorization.

10001031121310 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1000103112138.

The product of its (nonzero) digits is 18, while the sum is 14.

Adding to 10001031121310 its reverse (1312113010001), we get a palindrome (11313144131311).

The spelling of 10001031121310 in words is "ten trillion, one billion, thirty-one million, one hundred twenty-one thousand, three hundred ten".

Divisors: 1 2 5 10 1000103112131 2000206224262 5000515560655 10001031121310