Base | Representation |
---|---|
bin | 10110101111010110100000… |
… | …110010001100101010001010 |
3 | 111010002221220022110100000110 |
4 | 112233112200302030222022 |
5 | 101102040022304012340 |
6 | 552412231342415150 |
7 | 30031362041124006 |
oct | 2657264062145212 |
9 | 433087808410013 |
10 | 100011011000970 |
11 | 29959482479183 |
12 | b2729792914b6 |
13 | 43a5cc8422934 |
14 | 1a9a7b7347706 |
15 | b867b12d3680 |
hex | 5af5a0c8ca8a |
100011011000970 has 64 divisors (see below), whose sum is σ = 243581034072960. Its totient is φ = 26276764259328.
The previous prime is 100011011000969. The next prime is 100011011001001. The reversal of 100011011000970 is 79000110110001.
It is a super-2 number, since 2×1000110110009702 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 65423379 + ... + 66934598.
It is an arithmetic number, because the mean of its divisors is an integer number (3805953657390).
Almost surely, 2100011011000970 is an apocalyptic number.
100011011000970 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
100011011000970 is an abundant number, since it is smaller than the sum of its proper divisors (143570023071990).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
100011011000970 is a wasteful number, since it uses less digits than its factorization.
100011011000970 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 132358359.
The product of its (nonzero) digits is 63, while the sum is 21.
Adding to 100011011000970 its reverse (79000110110001), we get a palindrome (179011121110971).
The spelling of 100011011000970 in words is "one hundred trillion, eleven billion, eleven million, nine hundred seventy", and thus it is an aban number.
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