1000110122021 has 2 divisors, whose sum is σ = 1000110122022. Its totient is φ = 1000110122020.

The previous prime is 1000110121973. The next prime is 1000110122023. The reversal of 1000110122021 is 1202210110001.

1000110122021 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 985205130625 + 14904991396 = 992575^2 + 122086^2 .

It is an emirp because it is prime and its reverse (1202210110001) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1000110122021 is a prime.

Together with 1000110122023, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1000110121993 and 1000110122011.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1000110122023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500055061010 + 500055061011.

It is an arithmetic number, because the mean of its divisors is an integer number (500055061011).

Almost surely, 2^{1000110122021} is an apocalyptic number.

It is an amenable number.

1000110122021 is a deficient number, since it is larger than the sum of its proper divisors (1).

1000110122021 is an equidigital number, since it uses as much as digits as its factorization.

1000110122021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8, while the sum is 11.

Adding to 1000110122021 its reverse (1202210110001), we get a palindrome (2202320232022).

The spelling of 1000110122021 in words is "one trillion, one hundred ten million, one hundred twenty-two thousand, twenty-one".