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100011021112127 is a prime number
BaseRepresentation
bin10110101111010110100001…
…011000110001001100111111
3111010002221221000111000220202
4112233112201120301030333
5101102040032401042002
6552412232343234115
730031362223065416
oct2657264130611477
9433087830430822
10100011021112127
1129959488154904
12b27298074893b
1343a5cca552c78
141a9a7b881a47d
15b867b212e502
hex5af5a163133f

100011021112127 has 2 divisors, whose sum is σ = 100011021112128. Its totient is φ = 100011021112126.

The previous prime is 100011021112109. The next prime is 100011021112217. The reversal of 100011021112127 is 721211120110001.

It is a happy number.

Together with next prime (100011021112217) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 100011021112127 - 28 = 100011021111871 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 100011021112099 and 100011021112108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100011021112727) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50005510556063 + 50005510556064.

It is an arithmetic number, because the mean of its divisors is an integer number (50005510556064).

Almost surely, 2100011021112127 is an apocalyptic number.

100011021112127 is a deficient number, since it is larger than the sum of its proper divisors (1).

100011021112127 is an equidigital number, since it uses as much as digits as its factorization.

100011021112127 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 56, while the sum is 20.

Adding to 100011021112127 its reverse (721211120110001), we get a palindrome (821222141222128).

The spelling of 100011021112127 in words is "one hundred trillion, eleven billion, twenty-one million, one hundred twelve thousand, one hundred twenty-seven".