Base | Representation |
---|---|
bin | 1001000110001001000010… |
… | …1010110010011110010111 |
3 | 1022102002121121202221122221 |
4 | 2101202100222302132113 |
5 | 2302324233404012413 |
6 | 33134240313403211 |
7 | 2051361565606234 |
oct | 221422052623627 |
9 | 38362547687587 |
10 | 10001111000983 |
11 | 32064a1482553 |
12 | 1156347a09507 |
13 | 57714038b55b |
14 | 2680b08d278b |
15 | 12524274d68d |
hex | 91890ab2797 |
10001111000983 has 2 divisors, whose sum is σ = 10001111000984. Its totient is φ = 10001111000982.
The previous prime is 10001111000929. The next prime is 10001111001041. The reversal of 10001111000983 is 38900011110001.
It is a weak prime.
It is an emirp because it is prime and its reverse (38900011110001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10001111000983 - 29 = 10001111000471 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10001111000183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5000555500491 + 5000555500492.
It is an arithmetic number, because the mean of its divisors is an integer number (5000555500492).
Almost surely, 210001111000983 is an apocalyptic number.
10001111000983 is a deficient number, since it is larger than the sum of its proper divisors (1).
10001111000983 is an equidigital number, since it uses as much as digits as its factorization.
10001111000983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 25.
Adding to 10001111000983 its reverse (38900011110001), we get a palindrome (48901122110984).
The spelling of 10001111000983 in words is "ten trillion, one billion, one hundred eleven million, nine hundred eighty-three", and thus it is an aban number.
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