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10001210220143 is a prime number
BaseRepresentation
bin1001000110001001011010…
…0101010001111001101111
31022102002212112110210202122
42101202112211101321233
52302324434304021033
633134254220143155
72051364212140022
oct221422645217157
938362775423678
1010001210220143
11320654249035a
121156375097abb
13577157aba80c
142680bdb5d1b9
1512524b2eba98
hex91896951e6f

10001210220143 has 2 divisors, whose sum is σ = 10001210220144. Its totient is φ = 10001210220142.

The previous prime is 10001210220121. The next prime is 10001210220233. The reversal of 10001210220143 is 34102201210001.

10001210220143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10001210220143 - 212 = 10001210216047 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10001210220943) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5000605110071 + 5000605110072.

It is an arithmetic number, because the mean of its divisors is an integer number (5000605110072).

Almost surely, 210001210220143 is an apocalyptic number.

10001210220143 is a deficient number, since it is larger than the sum of its proper divisors (1).

10001210220143 is an equidigital number, since it uses as much as digits as its factorization.

10001210220143 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 10001210220143 its reverse (34102201210001), we get a palindrome (44103411430144).

The spelling of 10001210220143 in words is "ten trillion, one billion, two hundred ten million, two hundred twenty thousand, one hundred forty-three".