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10001300110 = 251000130011
BaseRepresentation
bin10010101000001111…
…11011101010001110
3221211000012200112121
421110013323222032
5130440313100420
64332230323154
7502561435234
oct112407735216
927730180477
1010001300110
11427252288a
121b314b94ba
13c35054179
146ac3c0954
153d80682aa
hex2541fba8e

10001300110 has 8 divisors (see below), whose sum is σ = 18002340216. Its totient is φ = 4000520040.

The previous prime is 10001300083. The next prime is 10001300119. The reversal of 10001300110 is 1100310001.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-3 number, since 3×100013001103 (a number of 31 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10001300093 and 10001300102.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10001300119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 500064996 + ... + 500065015.

It is an arithmetic number, because the mean of its divisors is an integer number (2250292527).

Almost surely, 210001300110 is an apocalyptic number.

10001300110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

10001300110 is a deficient number, since it is larger than the sum of its proper divisors (8001040106).

10001300110 is a wasteful number, since it uses less digits than its factorization.

10001300110 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1000130018.

The product of its (nonzero) digits is 3, while the sum is 7.

Adding to 10001300110 its reverse (1100310001), we get a palindrome (11101610111).

The spelling of 10001300110 in words is "ten billion, one million, three hundred thousand, one hundred ten".

Divisors: 1 2 5 10 1000130011 2000260022 5000650055 10001300110