10001301012211 has 2 divisors, whose sum is σ = 10001301012212. Its totient is φ = 10001301012210.

The previous prime is 10001301012193. The next prime is 10001301012229. The reversal of 10001301012211 is 11221010310001.

It is a happy number.

It is a balanced prime because it is at equal distance from previous prime (10001301012193) and next prime (10001301012229).

It is a cyclic number.

It is not a de Polignac number, because 10001301012211 - 2¹¹ = 10001301010163 is a prime.

It is a super-3 number, since 3×10001301012211³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 10001301012191 and 10001301012200.

It is not a weakly prime, because it can be changed into another prime (10001301022211) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5000650506105 + 5000650506106.

It is an arithmetic number, because the mean of its divisors is an integer number (5000650506106).

Almost surely, 2^{10001301012211} is an apocalyptic number.

10001301012211 is a deficient number, since it is larger than the sum of its proper divisors (1).

10001301012211 is an equidigital number, since it uses as much as digits as its factorization.

10001301012211 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 10001301012211 its reverse (11221010310001), we get a palindrome (21222311322212).

The spelling of 10001301012211 in words is "ten trillion, one billion, three hundred one million, twelve thousand, two hundred eleven".