Base | Representation |
---|---|
bin | 1001000110001001110010… |
… | …0110100001111100100011 |
3 | 1022102010010120111200120211 |
4 | 2101202130212201330203 |
5 | 2302330141132230144 |
6 | 33134312224514551 |
7 | 2051366546430622 |
oct | 221423446417443 |
9 | 38363116450524 |
10 | 10001311211299 |
11 | 3206594499521 |
12 | 11563a2a7ba57 |
13 | 5771729ba4b5 |
14 | 2680cd32b6b9 |
15 | 1252550ea034 |
hex | 9189c9a1f23 |
10001311211299 has 2 divisors, whose sum is σ = 10001311211300. Its totient is φ = 10001311211298.
The previous prime is 10001311211167. The next prime is 10001311211323. The reversal of 10001311211299 is 99211211310001.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10001311211299 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 10001311211299.
It is not a weakly prime, because it can be changed into another prime (10001312211299) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5000655605649 + 5000655605650.
It is an arithmetic number, because the mean of its divisors is an integer number (5000655605650).
Almost surely, 210001311211299 is an apocalyptic number.
10001311211299 is a deficient number, since it is larger than the sum of its proper divisors (1).
10001311211299 is an equidigital number, since it uses as much as digits as its factorization.
10001311211299 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 31.
The spelling of 10001311211299 in words is "ten trillion, one billion, three hundred eleven million, two hundred eleven thousand, two hundred ninety-nine".
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