10001311211167 has 2 divisors, whose sum is σ = 10001311211168. Its totient is φ = 10001311211166.

The previous prime is 10001311211117. The next prime is 10001311211299. The reversal of 10001311211167 is 76111211310001.

10001311211167 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10001311211167 - 2¹⁵ = 10001311178399 is a prime.

It is a super-2 number, since 2×10001311211167² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10001311211117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5000655605583 + 5000655605584.

It is an arithmetic number, because the mean of its divisors is an integer number (5000655605584).

Almost surely, 2^{10001311211167} is an apocalyptic number.

10001311211167 is a deficient number, since it is larger than the sum of its proper divisors (1).

10001311211167 is an equidigital number, since it uses as much as digits as its factorization.

10001311211167 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 252, while the sum is 25.

Adding to 10001311211167 its reverse (76111211310001), we get a palindrome (86112522521168).

The spelling of 10001311211167 in words is "ten trillion, one billion, three hundred eleven million, two hundred eleven thousand, one hundred sixty-seven".