Base | Representation |
---|---|
bin | 10010101000010000… |
… | …00101011100101001 |
3 | 221211000021201112110 |
4 | 21110020011130221 |
5 | 130440320341301 |
6 | 4332231232533 |
7 | 502561663146 |
oct | 112410053451 |
9 | 27730251473 |
10 | 10001340201 |
11 | 427254aa16 |
12 | 1b31518749 |
13 | c350694a8 |
14 | 6ac3d13cd |
15 | 3d80750d6 |
hex | 254205729 |
10001340201 has 32 divisors (see below), whose sum is σ = 13828510080. Its totient is φ = 6425362944.
The previous prime is 10001340199. The next prime is 10001340203. The reversal of 10001340201 is 10204310001.
It is a happy number.
It is an interprime number because it is at equal distance from previous prime (10001340199) and next prime (10001340203).
It is not a de Polignac number, because 10001340201 - 21 = 10001340199 is a prime.
It is a super-2 number, since 2×100013402012 (a number of 21 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (10001340203) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 9149811 + ... + 9150903.
It is an arithmetic number, because the mean of its divisors is an integer number (432140940).
Almost surely, 210001340201 is an apocalyptic number.
It is an amenable number.
10001340201 is a deficient number, since it is larger than the sum of its proper divisors (3827169879).
10001340201 is a wasteful number, since it uses less digits than its factorization.
10001340201 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2025.
The product of its (nonzero) digits is 24, while the sum is 12.
Adding to 10001340201 its reverse (10204310001), we get a palindrome (20205650202).
The spelling of 10001340201 in words is "ten billion, one million, three hundred forty thousand, two hundred one".
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