1000139983 has 2 divisors, whose sum is σ = 1000139984. Its totient is φ = 1000139982.

The previous prime is 1000139947. The next prime is 1000140013. The reversal of 1000139983 is 3899310001.

It is a strong prime.

It is an emirp because it is prime and its reverse (3899310001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1000139983 - 2¹³ = 1000131791 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1000139923) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500069991 + 500069992.

It is an arithmetic number, because the mean of its divisors is an integer number (500069992).

Almost surely, 2^1000139983 is an apocalyptic number.

1000139983 is a deficient number, since it is larger than the sum of its proper divisors (1).

1000139983 is an equidigital number, since it uses as much as digits as its factorization.

1000139983 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5832, while the sum is 34.

The square root of 1000139983 is about 31624.9898498007. The cubic root of 1000139983 is about 1000.0466588229.

Adding to 1000139983 its reverse (3899310001), we get a palindrome (4899449984).

The spelling of 1000139983 in words is "one billion, one hundred thirty-nine thousand, nine hundred eighty-three".