10001424134311 has 2 divisors, whose sum is σ = 10001424134312. Its totient is φ = 10001424134310.

The previous prime is 10001424134269. The next prime is 10001424134329. The reversal of 10001424134311 is 11343142410001.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10001424134311 - 2¹⁷ = 10001424003239 is a prime.

It is a super-3 number, since 3×10001424134311³ (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10001424104311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5000712067155 + 5000712067156.

It is an arithmetic number, because the mean of its divisors is an integer number (5000712067156).

Almost surely, 2^{10001424134311} is an apocalyptic number.

10001424134311 is a deficient number, since it is larger than the sum of its proper divisors (1).

10001424134311 is an equidigital number, since it uses as much as digits as its factorization.

10001424134311 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 10001424134311 its reverse (11343142410001), we get a palindrome (21344566544312).

The spelling of 10001424134311 in words is "ten trillion, one billion, four hundred twenty-four million, one hundred thirty-four thousand, three hundred eleven".