1000201111997 has 2 divisors, whose sum is σ = 1000201111998. Its totient is φ = 1000201111996.

The previous prime is 1000201111979. The next prime is 1000201112021. The reversal of 1000201111997 is 7991111020001.

1000201111997 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with previous prime (1000201111979) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 998428617796 + 1772494201 = 999214^2 + 42101^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1000201111997 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1000201111697) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500100555998 + 500100555999.

It is an arithmetic number, because the mean of its divisors is an integer number (500100555999).

Almost surely, 2^{1000201111997} is an apocalyptic number.

It is an amenable number.

1000201111997 is a deficient number, since it is larger than the sum of its proper divisors (1).

1000201111997 is an equidigital number, since it uses as much as digits as its factorization.

1000201111997 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1134, while the sum is 32.

Adding to 1000201111997 its reverse (7991111020001), we get a palindrome (8991312131998).

The spelling of 1000201111997 in words is "one trillion, two hundred one million, one hundred eleven thousand, nine hundred ninety-seven".