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1000202212117 is a prime number
BaseRepresentation
bin11101000111000001011…
…00101001001100010101
310112121200210220212100201
432203200230221030111
5112341403231241432
62043253032340501
7132155641345513
oct16434054511425
93477623825321
101000202212117
11356202089949
12141a19844731
137341b148994
14365a52434b3
151b03e3aaee7
hexe8e0b29315

1000202212117 has 2 divisors, whose sum is σ = 1000202212118. Its totient is φ = 1000202212116.

The previous prime is 1000202212043. The next prime is 1000202212223. The reversal of 1000202212117 is 7112122020001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 873419215761 + 126782996356 = 934569^2 + 356066^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1000202212117 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1000202212094 and 1000202212103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1000202212417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500101106058 + 500101106059.

It is an arithmetic number, because the mean of its divisors is an integer number (500101106059).

Almost surely, 21000202212117 is an apocalyptic number.

It is an amenable number.

1000202212117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1000202212117 is an equidigital number, since it uses as much as digits as its factorization.

1000202212117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 112, while the sum is 19.

Adding to 1000202212117 its reverse (7112122020001), we get a palindrome (8112324232118).

The spelling of 1000202212117 in words is "one trillion, two hundred two million, two hundred twelve thousand, one hundred seventeen".