Base | Representation |
---|---|
bin | 10010101000010110… |
… | …11101111001111101 |
3 | 221211001221202201221 |
4 | 21110023131321331 |
5 | 130441032224223 |
6 | 4332302233341 |
7 | 502602345055 |
oct | 112413357175 |
9 | 27731852657 |
10 | 10002226813 |
11 | 4272aa6057 |
12 | 1b31885851 |
13 | c352b9c07 |
14 | 6ac582565 |
15 | 3d819cb5d |
hex | 2542dde7d |
10002226813 has 2 divisors, whose sum is σ = 10002226814. Its totient is φ = 10002226812.
The previous prime is 10002226783. The next prime is 10002226847. The reversal of 10002226813 is 31862220001.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9975415129 + 26811684 = 99877^2 + 5178^2 .
It is a cyclic number.
It is not a de Polignac number, because 10002226813 - 25 = 10002226781 is a prime.
It is a super-2 number, since 2×100022268132 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10002226853) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5001113406 + 5001113407.
It is an arithmetic number, because the mean of its divisors is an integer number (5001113407).
Almost surely, 210002226813 is an apocalyptic number.
It is an amenable number.
10002226813 is a deficient number, since it is larger than the sum of its proper divisors (1).
10002226813 is an equidigital number, since it uses as much as digits as its factorization.
10002226813 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 10002226813 its reverse (31862220001), we get a palindrome (41864446814).
The spelling of 10002226813 in words is "ten billion, two million, two hundred twenty-six thousand, eight hundred thirteen".
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