Base | Representation |
---|---|
bin | 101110100101001100… |
… | …0010011000011100100 |
3 | 100120012102002210002212 |
4 | 1131022120103003210 |
5 | 3114331211200200 |
6 | 113542031422552 |
7 | 10140614041523 |
oct | 1351230230344 |
9 | 316172083085 |
10 | 100032131300 |
11 | 394725918a2 |
12 | 17478684a58 |
13 | 958237c84a |
14 | 4bad4264ba |
15 | 2906e85035 |
hex | 174a6130e4 |
100032131300 has 144 divisors (see below), whose sum is σ = 229253576832. Its totient is φ = 37811558400.
The previous prime is 100032131299. The next prime is 100032131341. The reversal of 100032131300 is 3131230001.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 144763955 + ... + 144764645.
It is an arithmetic number, because the mean of its divisors is an integer number (1592038728).
Almost surely, 2100032131300 is an apocalyptic number.
100032131300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 100032131300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (114626788416).
100032131300 is an abundant number, since it is smaller than the sum of its proper divisors (129221445532).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
100032131300 is a wasteful number, since it uses less digits than its factorization.
100032131300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1398 (or 1391 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 14.
Adding to 100032131300 its reverse (3131230001), we get a palindrome (103163361301).
The spelling of 100032131300 in words is "one hundred billion, thirty-two million, one hundred thirty-one thousand, three hundred".
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