Base | Representation |
---|---|
bin | 10010101000100000… |
… | …00010000011101111 |
3 | 221211011012120020121 |
4 | 21110100002003233 |
5 | 130441334022341 |
6 | 4332344025411 |
7 | 502615460626 |
oct | 112420020357 |
9 | 27734176217 |
10 | 10003423471 |
11 | 4273743128 |
12 | 1b32162267 |
13 | c356187b2 |
14 | 6ac7b46bd |
15 | 3d83374d1 |
hex | 2544020ef |
10003423471 has 2 divisors, whose sum is σ = 10003423472. Its totient is φ = 10003423470.
The previous prime is 10003423447. The next prime is 10003423481. The reversal of 10003423471 is 17432430001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10003423471 - 25 = 10003423439 is a prime.
It is a super-3 number, since 3×100034234713 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10003423481) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5001711735 + 5001711736.
It is an arithmetic number, because the mean of its divisors is an integer number (5001711736).
Almost surely, 210003423471 is an apocalyptic number.
10003423471 is a deficient number, since it is larger than the sum of its proper divisors (1).
10003423471 is an equidigital number, since it uses as much as digits as its factorization.
10003423471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2016, while the sum is 25.
Adding to 10003423471 its reverse (17432430001), we get a palindrome (27435853472).
The spelling of 10003423471 in words is "ten billion, three million, four hundred twenty-three thousand, four hundred seventy-one".
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