Base | Representation |
---|---|
bin | 1001000110010011111001… |
… | …0011011111110110111111 |
3 | 1022102101010122100021210112 |
4 | 2101210332103133312333 |
5 | 2302401220134143012 |
6 | 33135441340100235 |
7 | 2051524021033544 |
oct | 221447623376677 |
9 | 38371118307715 |
10 | 10004024131007 |
11 | 32077568aa225 |
12 | 1156a1b53467b |
13 | 5774b5a7872a |
14 | 2682a9764bcb |
15 | 125363383122 |
hex | 9193e4dfdbf |
10004024131007 has 2 divisors, whose sum is σ = 10004024131008. Its totient is φ = 10004024131006.
The previous prime is 10004024130973. The next prime is 10004024131021. The reversal of 10004024131007 is 70013142040001.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (70013142040001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10004024131007 - 230 = 10002950389183 is a prime.
It is a super-2 number, since 2×100040241310072 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10004024133007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5002012065503 + 5002012065504.
It is an arithmetic number, because the mean of its divisors is an integer number (5002012065504).
Almost surely, 210004024131007 is an apocalyptic number.
10004024131007 is a deficient number, since it is larger than the sum of its proper divisors (1).
10004024131007 is an equidigital number, since it uses as much as digits as its factorization.
10004024131007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 672, while the sum is 23.
Adding to 10004024131007 its reverse (70013142040001), we get a palindrome (80017166171008).
The spelling of 10004024131007 in words is "ten trillion, four billion, twenty-four million, one hundred thirty-one thousand, seven".
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