100043555441 has 2 divisors, whose sum is σ = 100043555442. Its totient is φ = 100043555440.

The previous prime is 100043555429. The next prime is 100043555473. The reversal of 100043555441 is 144555340001.

It is an a-pointer prime, because the next prime (100043555473) can be obtained adding 100043555441 to its sum of digits (32).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 95209273600 + 4834281841 = 308560^2 + 69529^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-100043555441 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 100043555398 and 100043555407.

It is not a weakly prime, because it can be changed into another prime (100043555641) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50021777720 + 50021777721.

It is an arithmetic number, because the mean of its divisors is an integer number (50021777721).

Almost surely, 2^100043555441 is an apocalyptic number.

It is an amenable number.

100043555441 is a deficient number, since it is larger than the sum of its proper divisors (1).

100043555441 is an equidigital number, since it uses as much as digits as its factorization.

100043555441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24000, while the sum is 32.

Adding to 100043555441 its reverse (144555340001), we get a palindrome (244598895442).

The spelling of 100043555441 in words is "one hundred billion, forty-three million, five hundred fifty-five thousand, four hundred forty-one".