1000994783 has 2 divisors, whose sum is σ = 1000994784. Its totient is φ = 1000994782.

The previous prime is 1000994719. The next prime is 1000994821. The reversal of 1000994783 is 3874990001.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (3874990001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1000994783 - 2⁶ = 1000994719 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1000994783.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1000997783) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500497391 + 500497392.

It is an arithmetic number, because the mean of its divisors is an integer number (500497392).

Almost surely, 2^1000994783 is an apocalyptic number.

1000994783 is a deficient number, since it is larger than the sum of its proper divisors (1).

1000994783 is an equidigital number, since it uses as much as digits as its factorization.

1000994783 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54432, while the sum is 41.

The square root of 1000994783 is about 31638.5015922057. The cubic root of 1000994783 is about 1000.3314844393.

The spelling of 1000994783 in words is "one billion, nine hundred ninety-four thousand, seven hundred eighty-three".