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1000998365453 is a prime number
BaseRepresentation
bin11101001000100000010…
…01101110100100001101
310112200202022000122102022
432210100021232210031
5112400021040143303
62043504032535525
7132214446501332
oct16442011564415
93480668018368
101000998365453
11356580532709
121420003b15a5
1373517082a28
143663cc8a989
151b089223438
hexe91026e90d

1000998365453 has 2 divisors, whose sum is σ = 1000998365454. Its totient is φ = 1000998365452.

The previous prime is 1000998365441. The next prime is 1000998365483. The reversal of 1000998365453 is 3545638990001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 948983808964 + 52014556489 = 974158^2 + 228067^2 .

It is an emirp because it is prime and its reverse (3545638990001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1000998365453 - 230 = 999924623629 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1000998365395 and 1000998365404.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1000998365483) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500499182726 + 500499182727.

It is an arithmetic number, because the mean of its divisors is an integer number (500499182727).

Almost surely, 21000998365453 is an apocalyptic number.

It is an amenable number.

1000998365453 is a deficient number, since it is larger than the sum of its proper divisors (1).

1000998365453 is an equidigital number, since it uses as much as digits as its factorization.

1000998365453 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3499200, while the sum is 53.

The spelling of 1000998365453 in words is "one trillion, nine hundred ninety-eight million, three hundred sixty-five thousand, four hundred fifty-three".