Base | Representation |
---|---|
bin | 10110110000101001011110… |
… | …110111110011001111000111 |
3 | 111010102110212001011022120122 |
4 | 112300221132313303033013 |
5 | 101110020000432033123 |
6 | 552521203442052155 |
7 | 30040664531554313 |
oct | 2660513667631707 |
9 | 433373761138518 |
10 | 100100099486663 |
11 | 29993239613061 |
12 | b2880a094a05b |
13 | 43b1525449623 |
14 | 1aa0c2916cb43 |
15 | b88c7760bbc8 |
hex | 5b0a5edf33c7 |
100100099486663 has 2 divisors, whose sum is σ = 100100099486664. Its totient is φ = 100100099486662.
The previous prime is 100100099486657. The next prime is 100100099486729. The reversal of 100100099486663 is 366684990001001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 100100099486663 - 244 = 82507913442247 is a prime.
It is a super-2 number, since 2×1001000994866632 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100100099486603) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50050049743331 + 50050049743332.
It is an arithmetic number, because the mean of its divisors is an integer number (50050049743332).
Almost surely, 2100100099486663 is an apocalyptic number.
100100099486663 is a deficient number, since it is larger than the sum of its proper divisors (1).
100100099486663 is an equidigital number, since it uses as much as digits as its factorization.
100100099486663 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1679616, while the sum is 53.
The spelling of 100100099486663 in words is "one hundred trillion, one hundred billion, ninety-nine million, four hundred eighty-six thousand, six hundred sixty-three".
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